92k=-12k^2-160

Solution for 92k=-12k^2-160 equation:

92k=-12k^2-160

We move all terms to the left:

92k-(-12k^2-160)=0

We get rid of parentheses

12k^2+92k+160=0

a = 12; b = 92; c = +160;
Δ = b2-4ac
Δ = 922-4·12·160
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-28}{2*12}=\frac{-120}{24}
=-5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+28}{2*12}=\frac{-64}{24}
=-2+2/3
$